A 10 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 12 CM. the distance of the object from the lens is 18 cm. find the nature position and size of the image formed .
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Height of object= 10cm
Focal length = 12 cm
Object distance= -18cm
Image distance= ?cm
So, 1/v+1/u=1/f
1/v= 1/12-1/18
1/v=3/36-2/36
1/v=1/36
v=36cm
Now m=36/-18
m=-2
Nature of image:-
1.image is virtual and erect.
2.it is formed behind the lens.
3.it is diminished in size.
4.it cannot captured on screen.
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