Question

A 10 gm of sample mixture of calcium chloride and sodium chloride is treated with na2co3 to

Answer 1

CaCO3 +heat--->CaO +Co2
X gms               1.68gms
100                   56
[molecular mass of CaCO3=100u
molecular mass of CaO=56u]
cross multiply through the equation and solve for x grams of caco3
x=1.62x100/56
=2.89g
Cacl2 +Na2Co3 --->Caco3 +2 Nacl
x                             2.89g
111                         100
Again cross multiply through the equation and solve for x grams of Cacl2
x=2.89x 111/100
=3.2g
%CaCl2 in original mixture 3.2grams 
Cacl2 over 10gms mixture is 32%

Answer 2

the question isn't complete...