a 10 gram Bullet is shoot from a gun of 5 kg with a velocity of 400 metre per second what is the speed of the recoil of the gun
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Answer:
v(gun)= - 0.001*400/5
v(gun)= -2 m/s
Explanation:
use conservation of linear momentum
V1. M1 + V2. M2 =0+0
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