Question

a 10 gram bullet moving at 200 m/s stops after penetrating 5cm of wooden plank the average force exerted on bullet will be

Answer 1

Hi friend,

Mass= 10g= 0.01kg
u= 200m/s
v= 0m/s
s= 5cm= 0.05m

We know that,

v²= u²+2as
0= 40000+2×a×0.05
a= -400000m/s²

Also,
F= m×a=
0.01×-400000
= 【-4000N】Answer..

HOPE THIS HELPS YOU:-))