Question

A 10 kg block is set moving with initial speed of 6 m/s on a rough horizontal surface if the force of friction is 20N, approximately how far does the block travel before it stops​

Answer 1

Answer:

Explanation: apply kinematics with dynamic s

Answer 2

Answer:

The block travelled distance equals to 9 meters before it stops.​

Explanation:

Given, the mass of a block, $m = 10 Kg$

The initial speed of the block on rough horizontal surface , u = 6 m/s

The force of friction, F = 20N

We know that, the Newton's 2nd law: $F = ma$

From this we can calculate the acceleration of the block:-

$a =\frac{F}{m}$

$a=\frac{-20N}{10Kg}$

$a = -2\;m/s^2$

Negative sign shows the retardation in the motion of the block due to force of friction.

Now the final velocity of the block will be, v = 0

From the third equation of motion:

$v^2-u^2 = 2aS$

where S is the distance travelled by the block before it stops.

$(0)^2 - (6)^2 = 2(-2)S$

$4S = 36\;m$

$S = 9\;m$

Therefore, the block will cover the distance 9m before it stops.

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