A 10 kg body is dropped from a height of 20 m. what is its potential energy before dropping? what is its kinetic energy when it is 8.0 m high above the ground? what when it hits the ground?
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m=10kg. t=?
h=20m. p.e.=?
g=10m/s^2. k.e.=?
p.e.=mgh
=10×10×20
=2000j
2gs=v^2-u^2. (case ll)
2×10×8=v^2-0
=160=v^2
k.e.=1/2mv^2
=1/2×10×160
=800j
case lll
s=it+1/2gt^2.
20=0×t+1/2×10×t^2
20=5t^2
4=t^2
t=2s
h=20m. p.e.=?
g=10m/s^2. k.e.=?
p.e.=mgh
=10×10×20
=2000j
2gs=v^2-u^2. (case ll)
2×10×8=v^2-0
=160=v^2
k.e.=1/2mv^2
=1/2×10×160
=800j
case lll
s=it+1/2gt^2.
20=0×t+1/2×10×t^2
20=5t^2
4=t^2
t=2s
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