A 10-kg object moving at 20 m/s collides with a 10-kg object that is stationary. After the collision, the velocity of the second object is 20 m/s.
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Let V1 = 10m/s , mass of initially moving body = m1 = 10kg
masss of stationary body = m2 = 5kg , velocity after Collin = V2.
When m1 mass colloid with mass m2 which is at rest then bodies exert equal and opposite force then bodies will deforme but if bodies do not have tendency to regain it original shape then they move with same velocity let say that velocity is V2
Therefore , Fnet acting on system = 0
dp/dt =0
Change in moment = 0
Initial momentum = , final momentum
m1V1 + m2V2 = (m1+m2) V
10(10) +0 = (10+5)V
100/15 = V
V = 20/3 m/s = 6.7 m/s
masss of stationary body = m2 = 5kg , velocity after Collin = V2.
When m1 mass colloid with mass m2 which is at rest then bodies exert equal and opposite force then bodies will deforme but if bodies do not have tendency to regain it original shape then they move with same velocity let say that velocity is V2
Therefore , Fnet acting on system = 0
dp/dt =0
Change in moment = 0
Initial momentum = , final momentum
m1V1 + m2V2 = (m1+m2) V
10(10) +0 = (10+5)V
100/15 = V
V = 20/3 m/s = 6.7 m/s
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Answer:
Step-by-step explanation:
Let V1 = 10m/s , mass of initially moving body = m1 = 10kg
masss of stationary body = m2 = 5kg , velocity after Collin = V2.
When m1 mass colloid with mass m2 which is at rest then bodies exert equal and opposite force then bodies will deforme but if bodies do not have tendency to regain it original shape then they move with same velocity let say that velocity is V2
Therefore , Fnet acting on system = 0
dp/dt =0
Change in moment = 0
Initial momentum = , final momentum
m1V1 + m2V2 = (m1+m2) V
10(10) +0 = (10+5)V
100/15 = V
V = 20/3 m/s = 6.7 m/s
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