A 10 kg rock is dropped and hits the ground below at a speed of 60 m/s. Calculate the gravitational potential energy of the rock before it was dropped. You can ignore the effects of friction.
Answers
Answered by
11
solution:
Mass of body, m= 10kg
velocity, v= 60m/s
Now,kinetic energy on earth= potential energy at a that point [energy conservation]
so, kinetic energy= 1/2*m* v^2
= 1/2* 60(60)^2
= 30* 60*60
= 108000 joules
Mass of body, m= 10kg
velocity, v= 60m/s
Now,kinetic energy on earth= potential energy at a that point [energy conservation]
so, kinetic energy= 1/2*m* v^2
= 1/2* 60(60)^2
= 30* 60*60
= 108000 joules
Answered by
4
Answer:
its 18000J
Explanation: PE= 1/2m(v squared) PE= 1/2x10x60x60 = 18000j idk how that man pulled 30 from or anything
Similar questions