if x = - root 2 is a zero of p (x) x2+root 2x +k find the value of k
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p(x)=x²+√(2x)+k
p(-√2)=0 (given)
(-√2)²+√2(-√2)+k=0
2-2+k=0
k=0
p(-√2)=0 (given)
(-√2)²+√2(-√2)+k=0
2-2+k=0
k=0
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