Math, asked by muskanysn, 1 year ago

plz solve the probability question

Attachments:

muskanysn: I'm class 9th....can u tell me the combination formula?

Anonymous: Permaution and Combination??

muskanysn: hmm

Anonymous: Do u know about factorial??

muskanysn: hmm

Anonymous: So Acc. To combination formula

Anonymous: No. Of combinations of a from b=

muskanysn: leave it......I'll search on Google......Thanks for ur help :)

Anonymous: b factorial / a factorial * ( b-a) factorial

Anonymous: Oohk

Answers

Answered by siddhartharao77

1) The total number of outcomes in the word probability = 11!.

2) Given that there are 3 letters in between them.

If P is in the 1st position, Then L would be in the 5th position.

If P is in the 2nd position, Then L will be in the 6th position.

There are 7 such positions, the last one having P in the 7th position and L in the last position.

3) If L is in the 1st position, Then P is in the 5th position.

There are 7 such positions, The last one having L in the 7th position and P in the Last position.

Up to now, we have filled in 2(P and L) of the 11 letters in 7 + 7 = 14 ways.

4) The remaining 9 letters can be filled themselves in 9! ways.

The probability that the P and L letters have exactly 3 letters

= 14 * 9!/11!

= 14 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1/ 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1

= 14/11 * 10

= 14/110.

Hope this helps!

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