A 10 liter container filled with a gas to a pressure of 20 atmospheric pressure at 0°c . At what temperature will the pressure inside the container be 2.5 atmospheric pressure.
Answers
Answered by
1
Hey there !!!
PV=nRT
at constant volume
Pressure is directly proportional to temperature.
Initial pressure = 20 temp=273 K
Final pressure = 2.5 temp =t K
initial pressure/final pressure = initial temp/final temp
20/2.5 =273/t
t=273*2.5/20
t=34.125 K
PV=nRT
at constant volume
Pressure is directly proportional to temperature.
Initial pressure = 20 temp=273 K
Final pressure = 2.5 temp =t K
initial pressure/final pressure = initial temp/final temp
20/2.5 =273/t
t=273*2.5/20
t=34.125 K
Answered by
0
T1=0°C=273K
P1=20atm=760×20=15200mmHg
P2=2.5atm=760×2.5=1900mmHg
T2=?
P1/T1=P2/T2
15200/273=1900/T2
T2=1900×273/15200
=273/8
=34.125K
=34.125-273
=−238.875°C
P1=20atm=760×20=15200mmHg
P2=2.5atm=760×2.5=1900mmHg
T2=?
P1/T1=P2/T2
15200/273=1900/T2
T2=1900×273/15200
=273/8
=34.125K
=34.125-273
=−238.875°C
OmmPrakashNayak:
u tried it best 2 help me
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