Physics, asked by OmmPrakashNayak, 1 year ago

A 10 liter container filled with a gas to a pressure of 20 atmospheric pressure at 0°c . At what temperature will the pressure inside the container be 2.5 atmospheric pressure.

Answers

Answered by pankaj12je
1
Hey there !!!

PV=nRT

at constant volume 

Pressure is directly proportional to temperature.

Initial pressure = 20 temp=273 K

Final pressure = 2.5 temp =t K

initial pressure/final pressure = initial temp/final temp

20/2.5 =273/t

t=273*2.5/20

t=34.125 K
Answered by MridulAhi
0
T1=0°C=273K
P1=20atm=760×20=15200mmHg
P2=2.5atm=760×2.5=1900mmHg
T2=?
P1/T1=P2/T2
15200/273=1900/T2
T2=1900×273/15200
=273/8
=34.125K
=34.125-273
=−238.875°C

OmmPrakashNayak: u tried it best 2 help me
OmmPrakashNayak: *ur
MridulAhi1234: welcome
MridulAhi1234: answer is 341.25 according to this
MridulAhi1234: p1/t1=p2/t2
MridulAhi1234: 2/273=2.5/t2
OmmPrakashNayak: ya bro correct
MridulAhi1234: t2=2.5×273/2
MridulAhi1234: = 341.25
OmmPrakashNayak: hmm
Similar questions