If x=4/3 is the root of the ploynomial p(x)=6x3-11x2+kx-20,find the value of k
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p(x)=6x3-11x2+kx-20,
We have x=4/3 as its root so v can put value of x in given equation
P(4/3)= 6(4/3)^3-11(4/3)^2+k(4/3)-20
0= 6(64)/27-11(16/9)+4k/3-20
0= 128/9-176/9+4k/3-20
128-176+12k-180=0
12k= 228
K= 19
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