a 10 liter sample of nitrogen inside a rigid metal container at 10 degree celcius is placed inside an oven whose temp is 50 degree celcius. the pressure inside the container at 20 degree celcius was at 3 atm. what is tha pressure of the nitrogen after ots temperature is increased to 50 degree celcius
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Answer:
Answer: 3.31 atm
Explanation:
Given data:
The initial temperature of the container, T₁ = 20℃ = 20+273 = 293 K
The initial pressure of nitrogen inside the container, P₁ = 3.00 atm
The final temperature inside the oven, T₂ = 50℃ = 50+273 = 323 K
To find: the Pressure of nitrogen after its temperature is increased
Let the final pressure of the nitrogen after its temperature is increased be denoted as “P₂”.
According to the Gay Lussac’s Law,
P₁ / T₁ = P₂ / T₂
⇒ 3.00/293 = P2/323
⇒ P₂ = 0.01023 * 323 = 3.307 atm ≈ 3.31 atm
Hence, the pressure of the nitrogen after its temperature is increased to 3.31 atm.
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