Chemistry, asked by sanjaysharma19ow6dwo, 1 year ago

A 10 ml 0.1M aqueous solution of KxH(C2O4)y required 8 ml of a 0.1 M acidified KMnO4 solution. Hence the value of x is

Answers

Answered by aadharshshello
4

Explanation:

Solution:

C2+3O42- → CO2+4

n factor of KxH(C2O4)y ⇒ 2y

meq of salt = meq of KMnO4

1012y = 80.15

y=2

again x+1 = 2y

x=3

Answered by mariospartan
2

Given:

10 ml 0.1M aqueous solution requires 8 ml of a 0.1 M acidified KMnO4 solution

To Find:

The value of x

Explanation:

C₂+3O₄2- → CO₂+4

calculating the n factor for

KₓH(C₂O₄)y ⇒ 2y

1012y = 80.15

y = 8015/1012

y=2

Now solving for x we get

x+1 = 2y

Substituting the value of y here

x+1 = 2(2)

x = 4-1

we get, x=3

Answer- value of x is 3

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