A 10 ml 0.1M aqueous solution of KxH(C2O4)y required 8 ml of a 0.1 M acidified KMnO4 solution. Hence the value of x is
Answers
Answered by
4
Explanation:
Solution:
C2+3O42- → CO2+4
n factor of KxH(C2O4)y ⇒ 2y
meq of salt = meq of KMnO4
1012y = 80.15
y=2
again x+1 = 2y
x=3
Answered by
2
Given:
10 ml 0.1M aqueous solution requires 8 ml of a 0.1 M acidified KMnO4 solution
To Find:
The value of x
Explanation:
C₂+3O₄2- → CO₂+4
calculating the n factor for
KₓH(C₂O₄)y ⇒ 2y
1012y = 80.15
y = 8015/1012
y=2
Now solving for x we get
x+1 = 2y
Substituting the value of y here
x+1 = 2(2)
x = 4-1
we get, x=3
Answer- value of x is 3
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