a 100 kg man jumps into a swiming pool from a height of 5m . it takes 0.4 seconds for water to reduce his velocity zero.the average force exerted by the water on the man taking (g=10m/sec^2) is ..........
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Answer:
f = mg
= 100 * 10
= 1000N
v = u + gt
= o + 10 * 0.4
= 4m/ s
hope it may helpful
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