A 100 KW engine is operating between 217°C and 17°C. Calculate the amount of heat absorbed and the amount of heat rejected
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Efficiency (₩) =work done/heat=W/Q
Also ₩=1- (T2/T1)
Therefore W/Q=1 -(T2/T1)
None of heat and work is given?
Because I can't proceed further
Also ₩=1- (T2/T1)
Therefore W/Q=1 -(T2/T1)
None of heat and work is given?
Because I can't proceed further
Answered by
0
absence of heat and work??
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