a 100 metre long train crosses a man travelling at 5 km per hour in opposite direction at the time 7.2 seconds then the velocity of train is
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we apply a simple logic, if train and man cross each-other in opposite direction then respective velocity is equal to the addition of both the velocities.
suppose the velocity of train = v,
velocity of man = 5 km/h, time taken t= 7.2 s, distance = length of train = 100 m.
respective velocity = (v + 5) km/h
here we apply just a simple formula i.e. velocity = distance/time
(v+5) km/h = 100/7.2 m/s, Or v = 13.89 m/s - 5 km/h, Or (since 1 km/s = 5/18 m/s)
v= 13.89 m/s - 5*(5/18) m/s Or v= 13.89 - 1.389 m/s Or (since 1 m/s = 18/5 km/s)
v = 12.5 m/s Or 45 km/h
suppose the velocity of train = v,
velocity of man = 5 km/h, time taken t= 7.2 s, distance = length of train = 100 m.
respective velocity = (v + 5) km/h
here we apply just a simple formula i.e. velocity = distance/time
(v+5) km/h = 100/7.2 m/s, Or v = 13.89 m/s - 5 km/h, Or (since 1 km/s = 5/18 m/s)
v= 13.89 m/s - 5*(5/18) m/s Or v= 13.89 - 1.389 m/s Or (since 1 m/s = 18/5 km/s)
v = 12.5 m/s Or 45 km/h
shubh1729:
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This is your answer I hope it's right
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