Question

A 100 ml mixture of CO and CO2, is passed through a tube containing red hot charcoal. The volume
becomes 160 ml. The volumes are measured under the same conditions of temperature and pressure.
Amongst the following, select the incorrect statement
(A) Mole percent of CO2 in the mixture is 60.
(B) Mole fraction of CO in the mixture is 0.40
(C) The mixture contains 40 ml of CO2
The mixture contains 40 ml of CO​

Answer 1

Answer:

c. the mixtuer contains 40ml of co2 . The mixture contains 40ml of co

Answer 2

Answer:

Option C

Explanation:

Given : A 100 ml mixture of CO and CO2, is passed through a tube containing red hot charcoal. The volume  becomes 160 ml. The volumes are measured under the same conditions of temperature and pressure.

To find : Amongst the following, select the incorrect statement ?

Solution :

A 100 ml mixture of CO and $CO_2$

Let x ml of CO.

So, 100-x of $CO_2$

We know that, $C + CO_2 \rightarrow 2CO$

The final volume would be $x+(100-x)+(100-x)=160$

$x+100-x+100-x=160$

$200-x=160$

$x=200-160$

$x=40$

The amount is 40 ml of CO

100-40=60ml of  $CO_2$

Option C is incorrect.