A 100-N uniform ladder, 8.0 m long, rests against a smooth vertical wall. The coefficient of static friction between ladder and floor is 0.30. What minimum angle can the ladder make with the floor before it slips?
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Explanation:
No, that is not right. You can't multiply a force (100 N) by a dimensionless number (0.4) and end up with degrees.
You need to write a moment balance equation for for the ladder an angle of tilt that causes the friction force on the floor to equal the maximum static friction, which is 0.40^100 = 40 N
Write an equation for the total moment about the point where the ladder touches the wall, and set that moment equal to zero. Three terms will contribute: the ladder's mass acting through the center of the ladder, a horizontal friction force of 40 N, and an upward force at the wall of 100 N.
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