Question

A 100 V, 200 W bulb is to be operated on 220 V DC line. For 200 W power, how much resistance should be connected in series with the bulb?

Answer 1

P = V × i

200 = 100 × i

⇒ i = 2 A

Voltage drop across resistance = 220 – 100 = 120 V

⇒ 120 = i × R

120 = 2 × R

R = 60 Ω

Answer 2

Explanation:

Thank u.............❣️