Question

A 100 watt, 110 volt lamp is connected in series with an electrolyte cell containing $CdSO_4$ solution.

What mass of Cd will be deposited by the current flowing for 10 hours??


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Answer 1

hii mate here is your answer:-

current strength = watt/ volt

therefore,. 100/110= 0.909 amp..

now,t= 10×60×60 = 3600sec

E c.d= 12.4/2=6.2

w=E.i.t/96500. ( 1farad=96500c)

W= 0.909×10×60×60×6.2//96500

W=19.05~19.06gm

hence weight of CD deposit is 19.06gm

Hope it helps bro..

Answer 2

Explanation:

P=VI

I=100/110=0.91A