Math, asked by vennelathallapally36, 11 months ago

a plot is 60m long and 40m wide a path 3m wide is to be constructed around the plot find the area of path​

Answers

Answered by ShreyaSingh31
71
\textbf {\textsf { Mensuration }}

Given :-
• Length of the plot = 60m
• Breadth of the plot = 40m
• Breadth of the path = 3m

To Find :-
• Area of the path

Now if we consider the plot as rectangle and after the construction of path, we can conclude two rectangles :-
• Inner Rectangle • Outer Rectangle

Now,

Area of the outer rectangle = Length × Breadth
= 60m × 40m
=2400m²

Now to find the dimensions of outer rectangle,

• Length = 60m + ( 2 × 3 )m
= 60m + 6m
= 66m

• Breadth = 40m + ( 2 × 3 )m
= 40m + 6m
= 46m

Now,
Area of outer rectangle = Length × Breadth
= 66m × 46m
=3036m²

Now, Area of path = Area of outer rectangle - Area of inner rectangle

= 3036m² - 2400m²
= 636m²

Hence, the area of path is 636m²

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Answered by gsribrunda
1

Answer:

• Length of the plot = 60m

• Breadth of the plot = 40m

• Breadth of the path = 3m

To Find :-

• Area of the path

Now if we consider the plot as rectangle and after the construction of path, we can conclude two rectangles :-

• Inner Rectangle • Outer Rectangle

Now,

Area of the outer rectangle = Length × Breadth

= 60m × 40m

=2400m²

Now to find the dimensions of outer rectangle,

• Length = 60m + ( 2 × 3 )m

= 60m + 6m

= 66m

• Breadth = 40m + ( 2 × 3 )m

= 40m + 6m

= 46m

Now,

Area of outer rectangle = Length × Breadth

= 66m × 46m

=3036m²

Now, Area of path = Area of outer rectangle - Area of inner rectangle

= 3036m² - 2400m²

= 636m²

Hence, the area of path is 636m²

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