Question

A 100 watt bulb emits monochromatic wavelength 400nm. Calculate the no.of photons emitted per second by the bulb​

Answer 1

Explanation:

2.01*10^10

E=mhc/lamda

by substituting n is 2.01*10^10

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Answer 2

Answer:

Explanation:

Power of the bulb = 100 watt

= 100 Js-¹

Energy of the photon

E = hv = hc/lambda

= (6.626 × 10^-34 Js ×3 × 10^8 ms-¹)÷ 400 × 10^-9m

= 4.969 × 10^-19 J

= Number of photons emitted

= 100Js-¹/4.969×10^-19 J

= 2.012 × 10^20 S-¹