Question

substance of mass 5 kg is moving in y direction,force F=kt^2 is acting in the direction of motion,where k=15s^-2. The distance travelled by substance in the first 2 second_,and speed after 2 sec is_? plz dont spam​ plz ...give correct answer​

Answer 1

Answer:

hope it helps

Explanation:

We know that the Newton's second law of motion is F=

Δt

Δp

or change in momentum

or the gain in momentum is Δp=FΔt=Area under the F-t graph

The net area till the end of t=10s is consists of a trapezium with parallel side as 10second and 8−4=4second

and the separation being 20N so area or momentum is

2

sum×separation

=

2

(10+4)second×20N

=140Newtonsecond