Question

A 1000 kg vehicle moving with a speed of 20 m/s is brought to
50 metres:
1) Find the acceleration.

2)Calculate the unbalanced force acting on the vehicle.​

Answer 1

Answer:

A 1000 kg vehicle moving with a speed of 20 m/s is

brought to rest in a distance of 50 metres :

(1) Find the acceleration.

(2) Calculate the unbalanced force acting on the vehicle.

☆☆Answer ☆☆

$\mathbf \red{given}$

M=1000 kg(mass)

u=20m/s(initial position)

v=0m/s(final position)

s=50m(distance)

♡using newton's second equation of motion

(i)V²=u²+2as

0²=(20)²+2×a×50

0²=400+50a

-400=50a

a=-400/50

a=-4

(ii) we know that unbalanced force equal to mass × acceleration .

so, f=m×a

=>f=1000×-4

=>f=-4000N

Answer 2

Answer:

A 1000 kg vehicle moving with a speed of 20 m/s is

brought to rest in a distance of 50 metres :

(1) Find the acceleration.

(2) Calculate the unbalanced force acting on the vehicle.

☆☆Answer ☆☆

M=1000 kg(mass)

u=20m/s(initial position)

v=0m/s(final position)

s=50m(distance)

♡using newton's second equation of motion

(i)V²=u²+2as

0²=(20)²+2×a×50

0²=400+100a

-400=100a

a=-400/100

a=-4

(ii) we know that unbalanced force equal to mass × acceleration .

so, f=m×a

=>f=1000×-4

=>f=-4000N

Explanation: