Question

a 1000 turns solenoid has a length of 20 cm and cross-sectional area 5 cm^2. A coil of 100 turns is wound at the centre of the solenoid. calculate the magnetic flux through the coil if a current of 2A flows in the solenoid

Answer 1

Answer:

Magnetic flux through the coil is given as

$\phi = 6.28 \times 10^{-4} Wb$

Explanation:

Magnetic field due to long solenoid at its center is given as

$B = \frac{\mu_o N i}{L}$

so we have

$B = \frac{(4\pi \times 10^{-7})(1000)(2)}{0.20}$

$B = 0.01256 T$

now we know that magnetic flux through the coil is given as

$\phi = N BA$

$\phi = 100 (0.01256)(5 \times 10^{-4})$

$\phi = 6.28 \times 10^{-4} Wb$

#Learn

Topic : Magnetic flux

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