Question

a 1000kg car rounds a curve on a flat road of radius 50m at a speed of 15m/s. will the car make the turn or will it skid if the coefficient of friction is 0.60. justify

very urgent...plssss help

Answer 1

The centripetal force needed to make the vehicle turn is
Fc = m v² / r
m = mass of the car = 1000 kg
v = speed of the car = 15 m/s
r = radius of the turn = 50 m
Then
Fc = 1000 x 15² / 50 = 4500 N
This force must be supplied by the friction between tires and road surface.
The frictional force is
Ff = u m g
u = coefficient of static friction = 0.6
m = mass of the car = 1000 kg
g = gravity acceleration = 9.8 m/s²
Then
Ff = 0.6 x 1000 x 9.8 = 5880 N
The frictional force is more than sufficient to keep the car turning, so the car will not skid.