A 1000kg car strikes a tree at 30km/h and comes to a stop in 0.15 s. Find its initial momentum and the average force on the car while it is beong stopped.
Answers
Answer:
Answer on Question 81843, Physics, Mechanics, RelativityQuestion:A1000푘푔car strikes a tree at 30푘푚ℎ⁄and comes to a stop in 0.15푠. Find the initial momentum and average force on the car while it is being stopped?Solution:Let’s first convert 푘푚ℎ⁄to 푚푠⁄:푣푖=30푘푚ℎ∙1000푚1푘푚∙1ℎ3600푠=8.33푚푠.We can find the initial momentum from the formula:푝푖=푚푣푖=1000푘푔∙8.33푚푠=8330푘푔∙푚푠.Finally, we can find the average force on the car while it is being stoppedfrom the definition of the impulse:퐽=푚∆푣=퐹푎푣푔∆푡,푚(푣푓−푣푖)=퐹푎푣푔∆푡,퐹푎푣푔=푚(푣푓−푣푖)∆푡=1000푘푔∙(0푚푠−8.33푚푠)0.15푠=−55533푁.The sign minus indicates that the average force on the caris directed opposite to the motion of the car.Answer:푝푖=8330푘푔∙푚푠.퐹푎푣푔=55533푁, in opposite direction to the motion of the car.
Answer:
Two masses of 9.0×1024kg and 5.0×1024kg respectively, are separated by 1.6×1011m. A third mass is placed between the other two masses, such that it remains stationary. How far from the 9.0×1024kg mass is the third mass placed? Give your answer in giga-metres (Gm) but without a unit. Give your answer to two significant figures.
Explanation:
Two masses of 9.0×1024kg and 5.0×1024kg respectively, are separated by 1.6×1011m. A third mass is placed between the other two masses, such that it remains stationary. How far from the 9.0×1024kg mass is the third mass placed? Give your answer in giga-metres (Gm) but without a unit. Give your answer to two significant figures.