a 1000kg lift is supported by a cable that can support 2000kg the shortest distance in which the lift can be stopped when its descending with a speed of 2.5 m/s (g=10)
Answers
Answered by
3
Answer:
0.25 sec
Explanation:
The lift will be stopped when the max tension becomes equal to downward force
here the mass of the lift is 100
more 1000 N of force is needed in downward direction to stop the lift
ie the net accelaration (g+a) =20
a= 10 m/s^2
the final velocity of lift = 0=v , u=2.5
from v=u+at
2.5=10t
t=0.25sec
Answered by
0
Answer:5/16
Explanation:v2_u2=2as
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