A 1000kg vehicle moving with a speed of 10m/s is brought to rest in a distance of 50m by the application of brakes. calculate its accleration and the force acting on the vehicle
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♦Given that =>
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➰Mass M = 1000 kg
➰Initial Velocity u = 10m/s
➰Final Velocity v = 0
➰Distance s = 50 m
♦Using the Third Equation of Motion ,
V² - U² = 2as
(0)² - (10)² = 2 × a × 50
=> 100 = 100a
=> Acceleration a = 1 m/s²
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♦Force F = Mass M × acceleration a
=> F = 1000 × 1
=> F = 1000 N
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=============================================================
--------
==========================================================
♦Given that =>
==============
➰Mass M = 1000 kg
➰Initial Velocity u = 10m/s
➰Final Velocity v = 0
➰Distance s = 50 m
♦Using the Third Equation of Motion ,
V² - U² = 2as
(0)² - (10)² = 2 × a × 50
=> 100 = 100a
=> Acceleration a = 1 m/s²
=======================
♦Force F = Mass M × acceleration a
=> F = 1000 × 1
=> F = 1000 N
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