A 1000kg vehicle moving with a speed of 20m/s is brought to rest in a distanceof 50m calculate the unbalanced force acting on the vehicle
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Answered by
3
Answer:
Explanation:
F=ma
m=1000kg
BY applying newton's 3rd eq.
0=u^2-2as(as a is -ve)
u^2=100a
20^2=100a
400=100a
a=10 m/s^2
F=1000*10
=10000 N
Answered by
0
Answer:first find its acceleration using
Explanation:
Answer=8000N
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