Physics, asked by ashisiitm, 9 months ago

A 1000W heater is used for 1 hr everyday for 30 days (around 1 month). Find the cost of electricity if the rate is Rs. 3/unit.

Answers

Answered by vlaxmisrinivasu
22

Explanation:

hey mate here is ur answer

1000× 1×30= 30000

cost of electricity per unit I rs 3

so.. 30000/1000= 30kw/h

so 1kilowatt is equal to 1unit

30 kilowatt is equal to 30 units

so 30×3= rs 90

hope it helps you please mark me as brainliest plsssss

Answered by VineetaGara
4

Given,

A 1000W heater is used for 1 hr every day for 30 days (around 1 month).

The total cost of each unit of electricity = Rs. 3

To find,

The total cost of electricity.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Power (P)= Energy consumed (E) ÷ Time (T)

=> Energy consumed (E) = Power (P) x Time (T)

Now, according to the question;

Total units of energy consumed in one day by the heater = Power (P) x Time (T)

= 1000 W x 1 hour

= 1000 Wh = 1 kWh = 1 electrical unit

( Since 1 kWh = 1 electrical unit )

So, the total units of energy consumed in 30 days by the heater

= (units of energy consumed in one day by the heater)×30 days

= 1 electrical unit × 30 days

= 30 electrical units

Now, according to the question;

The total cost of electricity consumed by the heater in the 30 days (one month)

= (total units of energy consumed in 30 days by the heater)×(cost of each unit of electricity)

= 30 electrical units × Rs. 3

= Rs. 90

Hence, the total cost of electricity consumed by the heater in the 30 days (one month) is equal to Rs. 90.

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