A 100cm cube block has on mass of 395g.find its relative density
Answers
Answered by
22
Side of cube=100 cm
Volume=100*100*100
Density =m/v
=395/10^6
=395*10^-6
Relative density = density of cube/density of water
=395*10^-6/1
=395*10^-6
Volume=100*100*100
Density =m/v
=395/10^6
=395*10^-6
Relative density = density of cube/density of water
=395*10^-6/1
=395*10^-6
Answered by
9
volume of the given cube block = ( 100 ) cm^ 3
= 1000000 cm^3 so, its density = mass / volume = 395/1000000
= 3.95 * 10^ -4 g/ cm^3
since the relative density of any substance is defined as the ratio of the density of the substance to the density of water.
Also the density of water is 1 g / cm^3.
therefore the relative density of the cube block = density of cube block / density of water
= (3.95 * 10^ -4 g/ cm^3) / (1 g / cm^3)
= 3.95 * 10^ -4
= 1000000 cm^3 so, its density = mass / volume = 395/1000000
= 3.95 * 10^ -4 g/ cm^3
since the relative density of any substance is defined as the ratio of the density of the substance to the density of water.
Also the density of water is 1 g / cm^3.
therefore the relative density of the cube block = density of cube block / density of water
= (3.95 * 10^ -4 g/ cm^3) / (1 g / cm^3)
= 3.95 * 10^ -4
udaykiranreddy:
Both answers are same
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