Question

rs9000 for 2 years 4 months at 10% per annum compounded annually

Answer 1

First we have to find simple interest for
T=4 months=4/12
P=9, 000
R=10
S.I =(P×R×T)/100.
. . =(9, 000×10×4)/(100×12)
. . =Rs300
Compound interest for
P=9, 000
T=2
R=10%
Amount=P(1+R/100)power n
=9, 000(1+10/100)power 2
=9, 000(1+1/10)power 2
=9, 000{(10+1)}power 2
=9, 000(11)power 2
=9, 000×11×11
=Rs 1,08,900
Amount =Rs 1,08,900
Compound interest=1,08,900–9,000
C.I=Rs 1,080,000
Total C.I=Rs 1,08,000+Rs 300
=1,08,300.

Answer 2

Answer:

amount=11253

CI=2253

Step-by-step explanation:

FORMULA= AMOUNT=₹P×(1+R/100)×(1+TIME×R/100

AMOUNT= 9000×(1+10/100)×(1+12/4×10/100

SOLVE IT YOU GOT AMOUNT=11253

THEN CAMPOUND INTREST= AMOUNT–PRINCIPAL

11253–9000=2253

CI = 2253

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