A 10cm long stick is kept in front of a concave mirror having focal length of 10cm in auch a way that the end of the stick closest to the pole is at a distance of 20cm. What will be the length of the image?
Answers
Answered by
7
1/u+1/v=1/f
1/v=1/f-1/u
u/v=u/f-1= -20cm / -10cm
2-1=1
u/v=1
m=h2/h1=v/u
h2=-v/u×h1
=1×h1= -1×10=-10cm
the minus sign shows that image is invertad
hence the length of the image is 10 cm
1/v=1/f-1/u
u/v=u/f-1= -20cm / -10cm
2-1=1
u/v=1
m=h2/h1=v/u
h2=-v/u×h1
=1×h1= -1×10=-10cm
the minus sign shows that image is invertad
hence the length of the image is 10 cm
Gunjan2003:
please make it brainleast if it help you
please!!!
Similar questions