Question

a 10cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 12cm. the distance of the object from the lens is 18cm. find the nature, position and size of the formed​

Answer 1

hey there is answer !!!

I hope you help ....

data given .....

Focal length = 12 cm = f

Distance of object lens = u = -18 cm

Object height = h = 10 cm

Convex lens .... for this lens ... using formula ..

1/u - 1/v = 1/f

putting the valve .....of u ,v , and f we get....

1/v = 1/f + 1/u

1/v = 1 /12 + 1/-18

therefore ....

v = 36 cm

................................

magnification .....of image .....

therefore ..

m = v/u = h'/h

m = 36 /-18 = h'/10

h' = -20 cm

(size of the image)

Nature of the image is Real and inverted.

smart abhishek

regards you ...

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Answer 2

Answer:

hope it is helpful make me as branlist. Answered 5 months, 1 week ago

Focal length = 12 cm = f

Distance of object lens = u = -18 cm

Object height = h = 10 cm. after this confex lens and v=36 cm is given in the picture.....