Question

A 10kg iron bar (specific heat 0.11) at 80°C is placed on a block of ice. How much ice will melt?

Answer 1

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Answer 2

Answer:

1.1 kg of ice will melt.

Explanation:

From the concept of calorimetry we have,

Heat lost by iron bar= Heat gained by the ice

$m_ic_i\Delta T=m\times L$      (1)

Where,

$m_i$=mass of the iron bar

$c_i$=specific heat of the iron bar

ΔT=change in temperature

m=mass of ice

L=latent heat of fusion of ice=80cal/g

From the question, we are having,

$m_i$=10kg

$c_i$=0.11 cal/g

ΔT=80°C-0°C=80°C

We get the following by inserting the values in equation (1):

$10\times 0.11\times 80=m\times 80$

$m=1.1 kg$

Hence, 1.1 kg of ice will melt.

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