Question

A 10kg weight is raised to a height of 2.0m with an accelaration of 1.5ms^-2. compute the work done, if g=10ms^-2

Answer 1

As per Newton's law

net force on a system is product of mass and acceleration

$F_{net} = ma$

$F - F_g = ma$

$F = F_g + ma$

$F = mg + ma$

given that

m = 10 kg

g = 10 m/s^2

a = 1.5 m/s^2

now from above equation

$F = 10*10 + 10 * 1.5$

$F = 100 + 15 = 115 N$

now the work done is given by

$W = F.d$

$W = 115* 2 = 230 J$

so the work done is bringing the mass upwards is 230 J

Answer 2

The answer is 230 joules.