A 10L closed cylinder contains 2g hydrogen nd 2g deuterium gas at 27 degree celsius . Find the internal pressure of the cylinder... Please solve it friends...
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Answer:
10L= 0.01 m^3
2gof hydrogen =2 mol. M=1g/mol
2g of deuterium = 2 mol
Explanation:
The molar mass of both hydrogen and deuterium is same so the total mole will be 4 moles
R= 8.314 kJ/kmol K
T= 27 degree = 273+27= 300 K
As we know that
Pv=nRT
P(0.01)=4(8.314)(300)
P=997,680 Pa
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