Physics, asked by abhinavgarg3032, 7 hours ago

A 10N force moves a body around a circular path of radius 50cm .What is work done in completing one revolution.

Answers

Answered by vikasviki97
0

Answer:

Data: F=10N, d=50cm=50/100=0.5m, W=? Solution:W=F. d= (10)(0.5) =5 J. Work done is 5 J around a circular path.

Explanation:

Data: F=10N, d=50cm=50/100=0.5m, W=? Solution:W=F. d= (10)(0.5) =5 J. Work done is 5 J around a circular path.

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