A 10N force moves around a circular path of radius 50cm.what is work done in completing one revolution? Solution plz
Answers
Answered by
3
Explanation:
answer may be 0 as Work is given by force.disp here disp. is 0
Answered by
1
Answer:
Radius, r=50 cm
Time period, T=40 s=
v
2πr
⇒v=
T
2πr
⇒v=
40
2π×50
⇒v=2.5π cm/s
Centripetal acceleration, a=
r
v
2
⇒a=
50
6.25π
2
⇒a=0.125π
2
cm/s
2
⇒a≈0.13π
2
cm/s
2
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