A = 11 * 22 * 33 * 44 * 55 * ........1010. How many zeroes will be there at the end of A ?
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The numbers appear to be multiples of 11, although pls reconfirm about the last number though, shouldn't it be 1100.
Assuming that its 1100, the numbers would go like:
11, 22, 33, 44, 55, 66, 77....110, 121.....220, 231....330, 341,..440, 451...550...660...770....880...990 ... and...1100
so that means 11 zeroes in the answe
Assuming that its 1100, the numbers would go like:
11, 22, 33, 44, 55, 66, 77....110, 121.....220, 231....330, 341,..440, 451...550...660...770....880...990 ... and...1100
so that means 11 zeroes in the answe
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