Question

A (-11,7) and B(-10,6) are points of trisection of a line segment PQ, the co-ordinates of P
and Q are
[ ]
A) (-12,8)(-9,5) B) (12,8)(9,-5) C) (-12,-8)(-9,-5) D) (12,-8)(-9,5)​

Answer 1

Answer:Let P=(a1,b1) and Q=(a2,b2). Given, A=(−11,7) and B = (-10, 6)

⇒A is the mid-point of the line segment PB.

∴A=(a1−102,b1+62)

(−11,7)=(a1−102,b1+62)

⇒a1=−12 and b1=8

⇒F=(−12,8) . Similarly , Q=(−9,5)

Step-by-step explanation: