Math, asked by mathes1, 1 year ago

A 115 M long and 64 M broad lawn has two roads inside it at right angle,one 2m wide , running parallel to its length, and the other 2.5 wide, running parallel to its breadth .find the cost of gravelling the roads at rupees 4. 60 per metre square

Answers

Answered by santy2
36
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Answered by nikitasingh79
76
Length of a lawn(l) = 115m
Breadth of a lawn (b) = 64 m

Width of lengthwise road(PQ)= 2.5 m
Width of breadththwise road (AB)= 2 m.

Area of road( ABCD)= 115×2= 230 m²

Area of road( PQRS)= 64×2.5= 160 m²

Area of common path EFGH= 2× 2.5= 5 m²

Area of the roads= (Area of road ABCD+ Area of road PQRS) - Area of Road EFGH

Area of the roads= 230+160-5

Area of the roads= 390-5= 385 m²

Rate of gravel = ₹ 4.60 per m²

Cost of gravelling the roads= 385 × 4.60= 1771

Hence, the Cost of gravelling the roads = ₹1771

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