Question

A 12.0 g sample of gas occupies 19.2 l at stp. what is the average molecular weight of this gas? 18.6 g/gmol 15.2 g/gmol 14 g/gmol 13.2 g/ gmol

Answer 1

Answer:

A 12.0 of gas sample of gas occupies 19.2L at STP. what is the molecule weight ... At n.t.p 22.4 L gas weighs =12.0×22.4/19.2=14.0g/mo l ...

Answer 2

Given :

12.0 g sample of gas occupies 19.2 L at STP

To Find :

The average molecular weight of this gas

Solution :

19.2 L volume is occupied by 12 gm of a gas at STP

We know, At STP, 1 gram-mole of any gas occupies a volume of 22.4 L

22.4 L volume will be occupied by $\frac{12}{19.2} * 22.4$ gm of the gas at STP

                                                        = 14 gm of the gas at STP

Hence, the average molecular mass of the sample of gas is 14 g/mol.