Question

A 12 kg gun is mounted on the wheel shots a 100gm projectile with a muzzle velocity of 1800m/s at an angle of 60. above the horizontal. find horizontal velocity of gun​

Answer 1

Answer:

1533. Find the number of terms and the common ratio.

31. If S, S, S, be the sums of the first n terms, 2n terms, 3n terms respectively

of a G.P., prove that

1)

( S.? +S, =S,(S, +S;)

(ii) S(S, -S) =(S+S)

ANSWER

256

97

1. i

(1) 1024 (ii) (i) s262 (iv)

os

Answer 2

Answer:

Use SI units:

The projectile mass M = 0.1kg

Only the horizontal, ie X- component of the muzzle velocity vector matters. This is:

V = 1800cos60 = 900 m/s

The momentum in the X-direction is:

P = MV = 0.1 x 900 = 90 kgm/s

Assuming the powder charge is sufficiently small compared to the projectile that we can neglect it, or it is included in the mass of the projectile(if they have approx the same exit velocity) or it is some kind of rail gun:):

Recoil momentum of the gun = 12 x Vgun = 90

So the recoil velocity of the gun is 90/12 = 7.5 m/s.