Math, asked by rnayonamitra, 6 months ago

A 12 litres cylinder contains a mixture of oxygen and nitrogen, the volume of oxygen being 40% of total volume. A few litres of the mixture is released and an equal amount of nitrogen is added. Then the same amount to f the mixture as before is released and replaced by nitrogen for the second time. As a result, the oxygen content becomes 10% of the total volume. how many litres of mixture os released each time?

Answers

Answered by souparnika6b

Answer:

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Answered by rajbharravi63

Step-by-step explanation:

Step-by-step explanation:oxy= 40% at start

Step-by-step explanation:oxy= 40% at startoxy = 10% end

Step-by-step explanation:oxy= 40% at startoxy = 10% end let = x amount of mix released each time

Step-by-step explanation:oxy= 40% at startoxy = 10% end let = x amount of mix released each time ( 12-x)

Step-by-step explanation:oxy= 40% at startoxy = 10% end let = x amount of mix released each time ( 12-x) 12---------------(12-x)

Step-by-step explanation:oxy= 40% at startoxy = 10% end let = x amount of mix released each time ( 12-x) 12---------------(12-x) 1----------------(12-x)/12

Step-by-step explanation:oxy= 40% at startoxy = 10% end let = x amount of mix released each time ( 12-x) 12---------------(12-x) 1----------------(12-x)/12 10% =40%*(1-x/12)²

Step-by-step explanation:oxy= 40% at startoxy = 10% end let = x amount of mix released each time ( 12-x) 12---------------(12-x) 1----------------(12-x)/12 10% =40%*(1-x/12)² 1/4 = (1-x/12)²

Step-by-step explanation:oxy= 40% at startoxy = 10% end let = x amount of mix released each time ( 12-x) 12---------------(12-x) 1----------------(12-x)/12 10% =40%*(1-x/12)² 1/4 = (1-x/12)² 1/2 =1-x/12

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