A 12 N horizontal force is applied to a 4 KG block on a rough horizontal surface. The block initially at rest if coefficient of static friction = 0.5 and coefficient of kinectic friction = 0.4, the frictional force on the block is?
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given that ,
》mass of block = 2kg
》force applied = 2.5
》coefficient of static friction, µs = 0.4
☆Maximum static frictional force,
fmax = µs × m × g = 0.4 × 2 × 9.8
=> fmax = 7.84 N
Since,
the applied force is less than the maximum static frictional force,
the frictional force on the block is equal to the applied force = 2.5 N.
☆it is due to the fact that static friction is a self adjusting force.
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