A 12 pF capacitor is connected to a 50 V battery. How much electrostatic energy is stored in the capacitor?
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C = 12pf =12×10^-12 f
V=50 v
Energy store in the capacitor=1/CV^2
U=1/2 ×12×10^-12 ×(50)^2
= 6×10^-12 × 2500
= 15000×10^-12
15×10^-9 joule
I hope this help u
V=50 v
Energy store in the capacitor=1/CV^2
U=1/2 ×12×10^-12 ×(50)^2
= 6×10^-12 × 2500
= 15000×10^-12
15×10^-9 joule
I hope this help u
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