Question

A 1200-kg car starting from rest attains a speed of 20.0 m/s in 40.0 s.
What is its acceleration?
What force is acting upon it?

Answer 1

Answer:

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Answer 2

Explanation:

u=0

v=20m/s

t=40 sec

acceleration (a) =(v-u) /t

=(20-0)/40=1/2=0.5m/s^2

Force acting upon

F=ma=1200*0.5N=600N

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